Нахождение расстояния между двумя точками

from math import dist
 
coords1 = [(1, 10), (1, 11)]
coords2 = [(0, 20), (20, 20)]
coords3 = [(100, 91, 87), (80, 35, 70)]
coords4 = [(0, 100, 20), (0, 0, 80)]
 
print(dist(*coords1))
print(dist(*coords2))
print(dist(*coords3))
print(dist(*coords4))

def dist(*args, **kwargs): # real signature unknown
    """
    Return the Euclidean distance between two points p and q.
    
    The points should be specified as sequences (or iterables) of
    coordinates.  Both inputs must have the same dimension.
    
    Roughly equivalent to:
        sqrt(sum((px - qx) ** 2.0 for px, qx in zip(p, q)))
    """
    pass

sqrt(sum((px - qx) ** 2.0 for px, qx in zip(p, q)))

c1 = [(1, 10), (1, 11)]
c2 = [(0, 20), (20, 20)]
c3 = [(100, 91, 87), (80, 35, 70)]
c4 = [(0, 100, 20), (0, 0, 80)]
 
d=0
for pair in zip(*c1):    # подставляй сюда вместо c1 - c2..c4 - получишь нужное расстояние
    d+=(pair[0]-pair[1])**2
print(d**0.5)

coords1 = [(1, 10), (1, 11)]
coords2 = [(0, 20), (20, 20)]
coords3 = [(100, 91, 87), (80, 35, 70)]
coords4 = [(0, 100, 20), (0, 0, 80)]
 
coords = [coords1] + [coords2] + [coords3] + [coords4]
d=0
for i in coords:
    for j in zip(*i):    
        d+=(j[0]-j[1])**2
    print(d**0.5)
    d = 0

coords1 = [(1, 10), (1, 11)]
coords2 = [(0, 20), (20, 20)]
coords3 = [(100, 91, 87), (80, 35, 70)]
coords4 = [(0, 100, 20), (0, 0, 80)]
 
for i in [coords1] + [coords2] + [coords3] + [coords4]:
    d=0
    for j in zip(*i):    
        d+=(j[0]-j[1])**2
    print(d**0.5)