Вывести всех свобоных агентов

from urllib.request import urlopen
from bs4 import BeautifulSoup
def get_links (url):
    html = urlopen(url)
    bsobj = BeautifulSoup(html,"html.parser")
    return bsobj
 
BASE_URL = "http://www.sovsport.ru/football/articles/981707-oleg-ivanov-perejdet-v-dinamo-tablica-transferov-rfpl"
soup = get_links(BASE_URL)
players = soup.findAll("p")
 
for player in players:
    freeplayers = player.contents[0]
    if freeplayers == "свободный агент":
        print (freeplayers)

import requests
from bs4 import BeautifulSoup
import re
 
 
main_url = 'http://www.sovsport.ru/football/articles/981707-oleg-ivanov-perejdet-v-dinamo-tablica-transferov-rfpl'
 
def get_page(url=main_url):
    page = requests.get(url)
    return page.text
 
def parse_page(page):
    parse_soup = BeautifulSoup(page, 'lxml')
    free_man = parse_soup.find_all('p')
    for value in free_man:
        try:
            my_find = value.text.replace('\xa0',' ').split(',')
            for find_value in my_find:
                if re.search('свободный', find_value):
                    print('{}:{}'.format(find_value.replace('(свободный агент)','').replace('Могут прийти:','').strip(), value.find_previous('h3').text))
        except TypeError as err:
            print('Error: ', err)
 
if __name__ == '__main__':
    start = get_page()
    parse_page(start)