Программа на вывод месяцев года, которые начинаются в один день недели

#!/bin/bash
 
now=`date +"%Y"`
other=${1:-0}
year=`expr "$other" \| "$now"`
months=(01 02 03 04 05 06 07 08 09 10 11 12)
days=()
names=(empty Monday Tuesday Wednesday Thursday Friday Saturday Sunday)
for i in ${months[@]}; do
    var1=`date -d "01/$i/$year" +"%b"`
    var2=`date -d "01/$i/$year" +"%u"`
    days[var2]=${days[var2]}$var1
done
 
for i in 1 2 3 4 5 6 7
do
echo "${names[i]} - ${days[i]}"
done

var1=`date -d "$i/01/$year" +"%b"`
    var2=`date -d "$i/01/$year" +"%u"`

#!/bin/bash
 
year=${1:-$(date +%Y)}
 
for j in {4..11}; do
        echo -n "$(date -d@$((86400*j)) +%a) "
        for i in {1..12}; do
                mon=$(date -d$year-$i-1 +%b%u | grep $j'$')
                echo -n "${mon//[1-7]/ }"
        done
        echo
done

#!/usr/bin/env bash
 
if [[ $# -ne 1 ]]; then
  echo -e "\033[31;1mАргумент вне допустимого диапазона.\033[0m"
  return
fi
 
declare -A hash
for i in `seq 1 12`; do
  read a b <<< $(date -d "$1-$i-1" +'%a %b')
  [[ ${hash[$a]}+$a ]] && hash[$a]="$(echo ${hash[$a]}), $b" || hash[$a]=$b
done
 
for i in "${!hash[@]}"; do
  echo -e "$i -${hash[$i]/,/}"
done
unset hash

#!/bin/bash
 
year=${1:-$(date +%Y)}
 
for j in {1..7}; do
        echo -n "$(date -d@$((86400*(j+3))) +%a) "
        for i in {1..12}; do
                mon=$(date -d$year-$i-1 +%b%u | grep $j'$')
                echo -n "${mon//[1-7]/ }"
        done
        echo
done

#!/usr/bin/env bash
 
[[ $# -eq 1 ]] && year=$1 || year=$(date +%Y)
echo {1..12}|xargs -d' ' -I{} date -d$year-{}-1 +'%a %b'|awk -F' ' '{a[$1]=a[$1] ? a[$1]","$2 : $2}END{for (i in a) if (length(a[i]) > 3) print i, a[i]}'