задача на логику

#include <iostream>
using namespace std;
 
int main()
{
   int a=130,b=136; //дата в днях
 
   while(a^b) {
     cout<<(a+b+abs(a-b))/2;
     system("pause");
     return 0;
   }
   cout<<"0";
   system("pause");
   return 0;
}

 int a=130,b=136;
 
   a^b ? cout<<(a+b+abs(a-b))/2 : cout<<"0";

int a=130,b=136;
 
   a-b ? cout<<(a+b+abs(a-b))/2 : cout<<"0";

#include <iostream>
 
template<typename T>
auto index(T a, T b=0)
{
    auto shift = sizeof(T) * 8 - 1;
    return (a - b != 0) | (a - b) >> shift;
}
 
int main()
{
    int y1 {1980}, m1 {1}, d1 {4};
    int y2 {1980}, m2 {1}, d2 {4};
    short data[3] {1, 0, 2};
 
    auto year = index(y1, y2) * 100;
    auto month = index(m1, m2) * 10;
    auto day = index(d1, d2);
    std::cout << data[index(year + month + day) + 1];
    return 0;
}

#include <iostream>
using namespace std;
 
bool f(int a, int b, int i)
{
    bool b_less_a=false;
    while(a-i)
    {
        !(b-i++)    ?  b_less_a=true,
                       a=i//для выхода из цикла тут ни break ни return неприменимы)
                    :  b_less_a=false
                                        ;
    }
return b_less_a ;
}
 
int main()
{
int a(1998), b(2000);
//int a(2000), b(1998);
//int a(2000), b(2000);
 
int i(0);
enum what_is {equal_as=0, less_than, more_than };
 
what_is whis =
(!(a-b))? equal_as
        : f(a, b, i)
                    ? less_than
                    : more_than
                                ;
////////////////
!whis   ? cout<<"b is equal to a\n"
        :
            whis==less_than ? cout<<"b is less than a"
                            : cout<<"b is more than a"
                                                        ;
return 0;
}

#include <iostream>
using namespace std;
 
int main()
{
int
a=101,b=30
//a=10,b=30
//a=101,b=101
;
 
!(a-b) ? bool(cout<< "equal\n") :
!a ?
bool(cout << "b is greater\n") :
(b/a) ?
bool(cout << "b is greater\n") :
    bool(cout << "a is greater\n")
                ;
return 0;
}

#include <iostream>
#include <numeric>
int foo(int x, int y)
{
    return (-1 * bool((y - x) & std::numeric_limits<int>::min()) + 2) * bool(x - y);
}
int main()
{
    std::cout << foo(42, 42) << " " << foo(100, 42) << " " << foo(42, 100) << std::endl;
}

int32_t foo(int32_t x, int32_t y)
{
    int32_t notequal = -1 * (((x - y) & std::numeric_limits<int32_t>::min() | (y - x) & std::numeric_limits<int32_t>::min()) >> 31);
 
    return ((((y-x)&std::numeric_limits<int32_t>::min())>>31)+2)*notequal;
}
int main()
{
    std::cout << foo(42, 42) << " " << foo(100, 42) << " " << foo(42, 100) << std::endl;
}

return ((unsigned)(-x) / (1+(unsigned)INT_MAX)) - ((unsigned)(x) / (1+(unsigned)INT_MAX));

int normalize(int i) {
    return (i+i)/(1+abs(i));
}
 
int main() {
    int p1[] = {2, 12, 1979};
    int p2[] = {1, 12, 1979};
 
    int d[] = { p1[0]-p2[0], p1[1]-p2[1], p1[2]-p2[2] };
    d[0] = 1*normalize(d[0]);
    d[1] = 2*normalize(d[1]);
    d[2] = 4*normalize(d[2]);
 
    int idx = 1+normalize(d[0]+d[1]+d[2]);
    const char* res[] = {"The first person is older then the second one.",
                         "Both of them are of the same age.",
                         "The second person is older then the first one."
    };
    std::cout << res[idx] << std::endl;
    return 0;
}

bool my_ternary(bool firstOrSecjnd, bool (*variantOne)(), bool (*variantTwo)());