программа которая переводит введенные числа в буквенную начертанию (надо немного исправить)

#include "stdafx.h"
#include <iostream>
using namespace std;

int main ( )
{ //char *k[9]={"sto","dvesti","3","4","5" ,"6","7","8","9"};
 char *s[19][15]=
 {
	{"null","odin","dva","try","4etire" ,"pyat","shest","sem","vosem","devat"},
	{"desyat","odinadcat","dvenadcat"," trindcat","4etirnadcat","pyatnadcat ",
	 "shistnadcat","simnadcat","vosemnad cat","deviatnadcat"},
	{"dvadcat"},
	{"tridcat"},
	{"sorok"},
	{"piatdeciat"},
	{"shestdeciat"},
	{"semdeiat"},
	{"vosemdeciat"},
	{"devianosto"},
	{"sto"},
	{"dvesti"},
	{"tristo"},
	{"4etiristo"},
	{"pyatsot"},
	{"shestsot"},
	{"semsot"},
	{"vosemsot"},
	{"devyatsot"}
 };

 for(int x=2;x<10;x++)
	for(int y=1;y<10;y++)
	{
		s[x][y]=s[0][y];
	}
	printf("vvedite 4islo v deapozone ot 1 do 999 :");
	int i=0;
	while (i);
	{
		scanf("%d",&i);
		if(i<37)
		{
			if(i<29)
			{ 
				if (i<20)
				{
					if (i<10) printf("%s",s[0]);
					else 
					{
						if(i>=10 && i<20) printf("%s",s[1][i%10]);
					}
				}
				else 
				{
					if((i%10)==0) printf("%s",s[i/10][0]);
					else {printf("%s %s\n",s[i/10][0],s[i/10][i%10]);
					}
				}
			}
			else
			{
				if((i%100)==0) printf("%s",s[i/100+9][0]);
				else 
				{
					if ((i%10)==0) printf ("%s %s", s[i/100+9][0],s[i/10][0]);
					else
					{
						printf ("%s %s %s",s[i/100+9][0],s[i/10][0],s[i/10][i%10]);
					}
				}
			}
		}
		else {printf ("error!\n");}
	}
 system("pause");
 return 0;
}