Сохранение изображения в БД SQLite

private void button2_Click(object sender, EventArgs e)
        {
            using (FileStream stream = new FileStream(pictureBox1.ImageLocation, FileMode.Open, FileAccess.Read))
            {
                BinaryReader br = new BinaryReader(stream);
                long totalBytes = new FileInfo(pictureBox1.ImageLocation).Length;
                byte[] buffer = br.ReadBytes((Int32)totalBytes);
                stream.Close();
                br.Close();
                SQLiteConnection con = new SQLiteConnection(string.Format("Data Source={0};", @"cyber1.db"));
                con.Open();
                SQLiteCommand cmd = new SQLiteCommand("insert into 'example' ('name') values('@photo')", con);
                cmd.Parameters.Add("@photo", DbType.Binary, 8000).Value = buffer;
                cmd.ExecuteNonQuery();
            }
        }
 
        private void button3_Click(object sender, EventArgs e)
        {
            SQLiteConnection connection = new SQLiteConnection(string.Format("Data Source={0};", @"cyber1.db"));
            SQLiteCommand command = new SQLiteCommand("SELECT example.name FROM example WHERE example.id = 1;", connection);
            connection.Open();
            IDataReader rdr = command.ExecuteReader();
               while (rdr.Read())
               {
                    byte[] a = (System.Byte[])rdr[0];
                    MemoryStream ms = new MemoryStream(a);
                    pictureBox2.Image = new Bitmap(ms);
               }
            connection.Close();
        }

connection.Open();
byte[] a = command.ExecuteScalar();
connection.Close();
 
MemoryStream ms = new MemoryStream(a);
pictureBox2.Image = new Bitmap(ms);