Найти точки сочленения в неориентированном графе

unit Unit1;
 
interface
 
uses
  Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
  Dialogs, StdCtrls, Grids, XPMan, ComCtrls;
 
type
  TForm1 = class(TForm)
    StringGrid1: TStringGrid;
    Label1: TLabel;
    Edit1: TEdit;
    Button1: TButton;
    Button2: TButton;
    XPManifest1: TXPManifest;
    procedure Button1Click(Sender: TObject);
  private
    { Private declarations }
  public
    { Public declarations }
  end;
 
var
  Form1: TForm1;
   nnew:array[1..n] of boolean;
   
implementation
 
{$R *.dfm}
 
procedure Pg (v:integer);
var
st:array[1..n] of integer;
yk,t,j:integer;
pp:boolean;
begin
nnew[v]:false;
//сдесь должен быть вывод V
for j:=1 to n do
if a[i,j]<>0 and (nnew[j]=True) then pg(j);
 
procedure TForm1.Button1Click(Sender: TObject);
var
n:integer;
i,x:integer;
begin
n:=strtoint(edit1.text);
stringgrid1.ColCount:=n+1;
stringgrid1.RowCount:=n+1;
x:=(n+1)*32;
stringgrid1.Height:=x;
stringgrid1.width:=x;
for i:=1 to n do begin stringgrid1.Cells[0,i]:=inttostr(i);
stringgrid1.Cells[i,0]:=inttostr(i); end;
stringgrid1.Visible:=true;
end;
 
end.

procedure Pg (v:integer);