Работа с базой данных (Задача о книгах)

SELECT TOP 1 * FROM 
(SELECT k.Kod_Knigi, k.Nazvanie, 
(k.Kolichestvo - t.kolvo) AS delta
  FROM [Книги] k RIGHT JOIN 
(SELECT Kod_Knigi, COUNT(*) AS kolvo FROM [Выдача] GROUP BY Kod_Knigi ) t 
ON  k.Kod_Knigi = t.Kod_Knigi
UNION
SELECT k.Kod_Knigi, k.Nazvanie,
k.Kolichestvo AS delta 
FROM [Книги] k
WHERE k.Kod_Knigi NOT IN (SELECT DISTINCT t.Kod_Knigi FROM [Выдача] t)) s 
ORDER BY s.delta DESC

SELECT r.*
FROM Выдача t, Читатели r
WHERE (DATE() - t.Data_vydachi) >= 4*30
AND r.Nomer_bileta = t.Nomer_bileta
AND t.Data_sdachi IS NULL

SELECT TOP 1 a.Nazvanie FROM 
(SELECT t.Kod_Knigi,k.Nazvanie, COUNT(*) AS kolvo FROM [Выдача] t, [Книги] k 
WHERE k.Kod_Knigi = t.Kod_Knigi
AND t.Data_vydachi BETWEEN :date1 AND :date2
GROUP BY t.Kod_Knigi, k.Nazvanie) a
ORDER BY a.kolvo DESC

SELECT r.FIO FROM
(SELECT t.Nomer_bileta, r.FIO, SUM(k.cena) AS summ
FROM Выдача t, Книги k, Читатели r
WHERE t.Data_sdachi IS NULL
AND k.Kod_Knigi = t.Kod_Knigi
AND r.Nomer_bileta = t.Nomer_bileta
GROUP BY t.Nomer_bileta, r.FIO) a
WHERE a.summ > 300

FROM Выдача, t