Как получить запрошенный URL или URI?

...
    public String getUri( HttpServletRequest req )
    {
        String uriPage = req.getRequestURI();
        
        return uriPage;
    }    
 ...

...
public static SiteSettings siteSettings = new SiteSettings();
...
 
    public static String templ() throws FileNotFoundException, IOException, URISyntaxException {
        
        HttpServletRequest request = null;
 
        String uriPg = siteSettings.getUri(request);
...

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
    <servlet>
        <servlet-name>ServletClass</servlet-name>
        <servlet-class>servlet.ServletClass</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>ServletClass</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>
    <session-config>
        <session-timeout>
            30
        </session-timeout>
    </session-config>
    <welcome-file-list>
        <welcome-file>ServletClass</welcome-file>
    </welcome-file-list>
</web-app>

type Exception report
 
message
 
descriptionThe server encountered an internal error () that prevented it from fulfilling this request.
 
exception
 
javax.servlet.ServletException: PWC1232: Exceeded maximum depth for nested request dispatches: 20
note The full stack traces of the exception and its root causes are available in the GlassFish Server Open Source Edition 3.1.2.2 logs.