Найти количество повторений каждого элемента

a,n=list(map(int, input().split()))
m=[0]*n
for i in range(n):
    m[i]=list(map(int, input().split()))
print(m)

import sys
import io
 
strin = """7 10
5 1
3 2
7 1
5 2
7 4
6 5
6 4
7 5
2 1
5 3"""
 
 
# var. 1
sys.stdin = io.StringIO(strin)
 
n, m = map(int, input().split())
tn = []
for i in range(m):
    tn.extend(input().split())
res = [tn.count(str(it)) for it in range(1, n+1)]
print(*res)
 
 
# var. 2
sys.stdin = io.StringIO(strin)
 
from collections import defaultdict
 
n, m = map(int, input().split())
tn = defaultdict(int)
for k in sys.stdin.read().split():
    tn[k] += 1
res = [it[1] for it in sorted(tn.items())]
print(*res)

arr = [[7, 10],
       [5,1],
       [3,2],
       [7,1],
       [5,2],
       [7,4],
       [6,5],
       [6,4],
       [7,5],
       [2,1],
       [5,3]
       ]
 
n = arr[0][0]
m = arr[0][1]
 
res = []
for i in range(n):
    res.append(0)
 
j = 0
while j <= m - 1:
    a = arr[j+1][0]
    b = arr[j+1][1]
    res[a - 1] = res[a - 1] + 1
    res[b - 1] = res[b - 1] + 1
    j += 1
 
print(res)

n,m=list(map(int, input().split()))
x=[0]*m
for i in range(m):
    x[i]=list(map(int, input().split())) 
sv=[0]*n
j = 0
while j <= m - 1:
    a = x[j][0]
    b = x[j][1]
    sv[a - 1] = sv[a - 1] + 1
    sv[b - 1] = sv[b - 1] + 1
    j += 1
print(' '.join(map(str, sv)))

n, m = map(int, input().split())
cross = [0] * (n + 1)
for tunnel in range(m):
    for k in map(int, input().split()):
        cross[k] += 1
print(*cross[1:])