Цикл for в качестве аргумента функции

ab = [1, 2, 3, 4, 5]
bs = [6, 7, 8, 9, 10]
 
for i in zip(ab, bs):
    print(i)

ab = [1, 2, 3, 4, 5]
bs = [6, 7, 8, 9, 10] 
def te(it1, it2):
    while (elem1:=next(it1, None)) is not None and (elem2:=next(it2, None)) is not None:
        yield elem1, elem2
print(*te(iter(ab), iter(bs)))

def func(a,b):
    f=True
    k=0
    while k<len(a) and k<len(b):
        if f:
            yield a[k]
        else:
            yield b[k]
            k+=1
        f=not f
        
        
for x in func([1,2,3,4],['a','b','c','d']):
    print(x)

t=5
d=8
p=120 
 
def one(a):
  b=5*(17.67*a/(a+10))
  return b
 
def two(v,p):
  c=0.622*50/(p-100)
  return c
 
def five(t,m):
  te=t*(1.0+0.6*m)
  return te
 
def seven(t,d,p):
  if (t > 0 and d > 0):
    v=one(d-273.15)
    m=two(5,p)
    tm=five(t,20)
  else:
    tm=5
  return tm
 
seven(298,222,750)

t=[7,9,12,25,38]
d=[18,5,2,32,21]
p=[17,58,72,98,19] 
 
def one(a):
  b=5*(17.67*a/(a+10))
  return b
 
def two(v,p):
  c=0.622*50/(p-100)
  return c
 
def five(t,m):
  te=t*(1.0+0.6*m)
  return te
 
def seven(t,d,p):
  if (t > 0 and d > 0):
    v=one(d-273.15)
    m=two(5,p)
    tm=five(t,20)
  else:
    tm=5
  return tm
 
seven(7,18,17)

for i in zip(t, d, p):
    print(seven(*i))