Как сделать так, чтобы когда элемент из нового списка меньше чем из старого выводились все элементы, которые меньше

    with open(f'data/number.txt') as file_0:
        number = file_0.read().count('0')
        old_number = number - 1
 
    with open(f'data/{number}. products.json', encoding='utf-8') as file_0:
        products_dict = json.load(file_0)
 
        for k, v in products_dict.items():
            all_new_products = f"{v['secret_price']}"
 
    with open(f'data/{old_number}. products.json', encoding='utf-8') as file_0:
        products_dict = json.load(file_0)
 
        for k, v in products_dict.items():
            all_old_products = f"{v['secret_price']}"
 
            if all_new_products < all_old_products:
                print(all_new_products)

with open(f'data/number.txt') as file_0:
    number = file_0.read().count('0')
    old_number = number - 1
 
with open(f'data/{number}. products.json', encoding='utf-8') as file_0:
        products_dict = json.load(file_0)
 
        #for k, v in products_dict.items():
            #all_new_products = f"{v['secret_price']}"
        all_new_products = [int(v['secret_price']) for k, v in products_dict.items()]
        n = len(all_new_products)
 
with open(f'data/{old_number}. products.json', encoding='utf-8') as file_0:
        products_dict = json.load(file_0)
 
        #for k, v in products_dict.items():
            #all_old_products = f"{v['secret_price']}"
        all_old_products = [int(v['secret_price']) for k, v in products_dict.items()]
 
res = [all_new_products[i] for i in range(n) if all_new_products[i] < all_old_products[i]]
print(*res, sep='\n')