Пусть дана целочисленная матрица размером n х m. Найдите номера строк

from random import randint
 
n = m = 10
arr = [[randint(10, 99) for _ in range(m)] for _ in range(n)]
# arr[7] = [0] * n
# arr[5] = [12] * n
# arr[1] = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
# arr[2] = [9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
# arr[3] = [2, 4, 6, 8, 0, 12, 14, 16, 18, 20]
# arr[4] = [1, 2, 3, 4, 5, 5, 4, 3, 2, 1]
print(*arr, sep='\n', end='\n\n')
 
all_zero = [i+1 for i in range(n) if all(el == 0 for el in arr[i])]
all_duplicates = [i+1 for i in range(n) if len(set(arr[i])) == 1]
all_even = [i+1 for i in range(n) if all(not el % 2 for el in arr[i])]
all_increase_or_decrease = [i+1 for i in range(n) if all(arr[i][j] > arr[i][j + 1] for j in range(n - 1)) or all(
    arr[i][j] < arr[i][j + 1] for j in range(n - 1))]
symmetric = [i+1 for i in range(n) if all(arr[i][j] == arr[i][n - j - 1] for j in range(n))]
 
print(all_zero)
print(all_duplicates)
print(all_even)
print(all_increase_or_decrease)
print(symmetric)

n=6; m=4
a=[[1,2,3,4],[0,0,0,0],[4,0,2,4],[3,3,3,3],[9,6,5,2],[7,2,2,7],[2,6,0,8]]
[print(*i) for i in a]
nul=[];eql=[];evn=[];mon=[];sym=[]
for i,x in enumerate(a):
    if x.count(0)==m:
        nul.append(i)
    if x.count(x[0])==m:
        eql.append(i)
    if sum(y%2 for y in x)==0:
        evn.append(i)
    if sum(x[y]<x[y+1] for y in range(m-1)) in (0,m-1) and i not in eql:
        mon.append(i)
    if x==x[::-1] and i not in eql:
        sym.append(i)
s='\n'
print(' нулевые:',*nul,s,'одинаковые:',*eql,s,'четные:',*evn,s,
      'монотонные:',*mon,s,'симметричные (неодинаковые):',*sym)