Вычислить значения выражений

#include "stdafx.h"
#include <clocale>
#include <math.h>
#include <iostream>
using namespace std;
int main()
{
setlocale( LC_ALL, "Russian" );
double x, z1, z2;
cout << "введите x" << endl;
cin >> x;
 
z1 =x*x+2x-3+(x+1)(sqrt(x*x-9))/x*x-2x-3+(x-1)(sqrt(x*x-9));
z2 =sqrt(x+3)/sqrt(x-3);
 
cout << "z1 " <<z1<<" , z2 " <<z2<<endl;
system("PAUSE");
return 0;
}

2. * x

#include <clocale>
#include <math.h>
#include <iostream>
using namespace std;
int main()
{
setlocale( LC_ALL, "Russian" );
double x, z1, z2;
cout << "введите x" << endl;
cin >> x;
 z1 =(x*x+(2*x)-3+(x+1)); sqrt(x*x-9) / (x*x-(2*x)-3+(x-1)); sqrt(x*x-9);
 z2 =sqrt(x+3)/sqrt(x-3);
cout << "z1 " <<z1<<" , z2 " <<z2<<endl;
system("PAUSE");
return 0;
}

#include <iostream>
#include <cmath>
 
using namespace std;
int main()
{
    setlocale( LC_ALL, "Russian" );
    double x, z1, z2;
    cout <<"Enter x: "; cin >>x;
    z1 =(x*x+2*x-3+(x+1)*sqrt(x*x-9))/(x*x-2*x-3+(x-1)*sqrt(x*x-9));
    z2 =sqrt(x+3)/sqrt(x-3);
    cout <<"z1="<<z1<<"  z2="<<z2<<endl;
system("pause");
return 0;
}