Как упростить решение задачи о подсчете количества

with open('input.txt', 'r', encoding='utf8') as olimp:
    lines = olimp.readlines()
tmp = []
# сначала забираю в список только класс и баллы
for i in range(len(lines)):
    line = lines[i].strip()
    line = line.split()
    tmp.append([int(line[2]), int(line[3])])
numb = [[9, 0], [10, 0], [11, 0]]
# далее нахожу макс балл по каждому классу
for i in range(len(tmp)):
    if tmp[i][0] == 9 and tmp[i][1] > numb[0][1]:
        numb[0][1] = tmp[i][1]
    elif tmp[i][0] == 10 and tmp[i][1] > numb[1][1]:
        numb[1][1] = tmp[i][1]
    elif tmp[i][0] == 11 and tmp[i][1] > numb[2][1]:
        numb[2][1] = tmp[i][1]
lol = [0] * 3
# теперь вычисляю количество максимальных баллов
for i in range(len(tmp)):
    if tmp[i][0] == 9 and tmp[i][1] == numb[0][1]:
        lol[0] += 1
    elif tmp[i][0] == 10 and tmp[i][1] == numb[1][1]:
        lol[1] += 1
    elif tmp[i][0] == 11 and tmp[i][1] == numb[2][1]:
        lol[2] += 1
print(*lol)

def filter_num(line):
    return [int(i) for i in line.split()[-2:]]
 
with open('test.txt') as olimp:
    tmp = [filter_num(line) for line in olimp.readlines()]
 
for number in sorted(set(i[0] for i in tmp)):
    list_ball = [i[1] for i in tmp if i[0] == number]
    print( list_ball.count(max(list_ball)) ,end = ' ')

with open('test.txt') as olimp:
    tmp =[list(map(int,line.split()[-2:])) for line in olimp.readlines()]
 
for number in sorted(set(i[0] for i in tmp)):
    list_ball = [i[1] for i in tmp if i[0] == number]
    print( list_ball.count(max(list_ball)) ,end = ' ')

with open('input.txt', 'r', encoding='utf8') as olimp:
    lines = olimp.readlines()
tmp = []

with open('test.txt') as olimp:
    tmp = [line.split()[-2:] for line in olimp.readlines()]

numb = [[9, 0], [10, 0], [11, 0]]

    if tmp[i][0] == 9 and tmp[i][1] > numb[0][1]:
        numb[0][1] = tmp[i][1]
    elif tmp[i][0] == 10 and tmp[i][1] > numb[1][1]:
        numb[1][1] = tmp[i][1]
    elif tmp[i][0] == 11 and tmp[i][1] > numb[2][1]:
        numb[2][1] = tmp[i][1]