Найти Количество повторяющихся элементов в List

def listcounter():
    mlist = ['Bob', 'Alice', 'Jane', 'Bob', 'Alice']
    print(*mlist)
    print(dict((i, mlist.count(i)) for i in set(mlist) if mlist.count(i) > 1))
    return mlist
 
 
if __name__ == '__main__':
    assert listcounter()

print(*mlist)

import csv
import re
 
with open('Hello123.csv', 'r') as f:
  reader = csv.reader(f)
  my_list = list(reader)
  my_list.sort()
 
 
def listToStringWithoutBrackets(my_list):
    return str(my_list).replace('[','').replace(']','').replace('\'', "")
x = str(listToStringWithoutBrackets(my_list))
# print(x)
a = x.split(",")
# print(a)
 
 
a = {i:a.count(i) for i in a if a.count(i) > 1}
 
for k,v in a.items():
    print(f'{k} - {v}'

import csv
import re
 
with open('Hello123.csv', 'r') as f:
reader = csv.reader(f)
my_list = list(reader)
my_list.sort()
 
 
def listToStringWithoutBrackets(my_list):
return str(my_list).replace('[','').replace(']','').replace('\'', "")
x = str(listToStringWithoutBrackets(my_list))
# print(x)
a = x.split(",")
# print(a)
 
 
a = {i:a.count(i) for i in a if a.count(i) > 1}
 
for k,v in a.items():
print(f'{k} - {v}'

lst = [['100 best wines'], ['100 parker points'], ['100 pp weine'], ['1855'], ['1966 whiskey'],
       ['20 wine'], ['2000 chateau mouton rothschild'], ['2000 chateau mouton rothschild'] ,
       ['2009 chateau pontet canet'], ['2009 chateau pontet canet'], ['2015 giscours margaux'],
       ['2015 larcis ducasse'], ['2016 chateau pontet canet'], ['2016 château léoville las cases'],
       ['89 haut brion'], ['99 point'], ['achim becker wein'], ['aiguilhe 2012'], ['aiguilhe 2014'],
       ['allee des chateaux'], ['2015 larcis ducasse'], ['2015 larcis ducasse'],
       ['alles wein'], ['alte bordeaux weine'], ['alte weine verkaufen'], ['alteisen ankauf nürnberg']]
    
    
 
dct = {}
for i in lst:
    key = ' '.join(i)
    dct[key] = dct.get(key,0) +1
print( *filter(lambda x : dct[x] > 1, dct),sep = '\n')