Забыл написать, язык Си.
Добавлено через 21 минуту
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| #include <iostream.h>
#include <stdio.h>
#include <conio.h>
int slid(int **matrix, int n)
{
int s=0;
for (int i=0; i<n;i++)
s+=matrix[i][i];
return s;
}
int max(int a, int b)
{
return (a>b ? a:b);
}
int main()
int n1, n2, n3;
int *m1, *m2, *m3;
printf("Vvedite rozmir pershoyi matrutsi: ");
scanf("%i", &n1);
m1=new int *[n1];
for (int i=0;i<n1;i++)
m1[i]=new int[n1];
printf("Vvedite element pershoyi matrutsi:");
for(int i=0;i<n1;i++)
for(int j=0;j<n1;j++)
scanf("%i", &m1[i][j];
int result =max(slid(m2,n2), max(slid(m1,n1), slid(m3,n3)));
printf("Persha matrutsa:=%i", slid(m1,n1))break;
printf("Druga matrutsa:=%i", slid(m2,n2))break;
printf("Tretya metrutsa:=%i", slid(m3,n3))break;
printf("Minimalna matrutsa:=%i", result));break;
}
getch();
} |
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Тотально неправильно, как исправить...
Добавлено через 19 часов 11 минут
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| #include <iostream>
using namespace std;
int sled(int **matrix, int n)
{
int s = 0;
for (int i = 0; i < n; i++)
s += matrix[i][i];
return s;
}
int max(int a, int b)
{
return (a > b ? a : b);
}
int main()
{
int n1, n2, n3;
int **m1, **m2, **m3;
cout << "Enter size of first matrix: ";
cin >> n1;
m1 = new int* [n1];
for (int i = 0; i < n1; i++) m1[i] = new int[n1];
cout << "Enter elements of first matrix: " << endl;
for (int i = 0; i < n1; i++)
for (int j = 0; j < n1; j++)
cin >> m1[i][j];
cout << "Enter size of second matrix: ";
cin >> n2;
m2 = new int* [n2];
for (int i = 0; i < n2; i++) m2[i] = new int[n2];
cout << "Enter elements of second matrix: " << endl;
for (int i = 0; i < n2; i++)
for (int j = 0; j < n2; j++)
cin >> m2[i][j];
cout << "Enter size of third matrix: ";
cin >> n3;
m3 = new int* [n3];
for (int i = 0; i < n3; i++) m3[i] = new int[n3];
cout << "Enter elements of third matrix: " << endl;
for (int i = 0; i < n3; i++)
for (int j = 0; j < n3; j++)
cin >> m3[i][j];
int result = max(sled(m2, n2), max(sled(m1, n1), sled(m3, n3)));
cout << "Trace of first matrix" << sled(m1, n1) << endl;
cout << "Trace of second matrix" << sled(m2, n2) << endl;
cout << "Trace of third matrix" << sled(m3, n3) << endl;
cout << "Maximal trace of matrixes: " << result << endl;
for (int i = 0; i < n1; i++) delete [] m1[i];
delete [] m1;
for (int i = 0; i < n2; i++) delete [] m2[i];
delete [] m2;
for (int i = 0; i < n1; i++) delete [] m3[i];
delete [] m3;
//system("pause");
return 0;
} |
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Помогите перевести в Си...
Что я пробовал:
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| #include <iostream.h>
#include <stdio.h>
int sled(int *matrix, int n)
{
int s = 0;
for(int i=0;i<n;i++)
{
s += matrix[i][i];
}
return s;
}
int max(int a, int b)
{
return (a > b ? a : b);
}
int main()
{
int n1, n2, n3;
int *m1, *m2, *m3;
printf("Enter size of first matrix: ");
scanf("%i", &n1);
m1 = malloc int* [n1];
for (int i = 0; i < n1; i++) m1[i] = malloc int[n1];
printf("Enter elements of first matrix: ")endl;
for (int i = 0; i < n1; i++)
for (int j = 0; j < n1; j++)
scanf("%i", m1[i][j]);
printf("Enter size of second matrix: ");
scanf("%i",&n2);
m2 = malloc int* [n2];
for (int i = 0; i < n2; i++) m2[i] = malloc int[n2];
printf("Enter elements of second matrix: ")endl;
for (int i = 0; i < n2; i++)
for (int j = 0; j < n2; j++)
scanf("%i", m2[i][j]);
printf("Enter size of third matrix: ");
scanf("%i",&n3);
m3 = malloc int* [n3];
for (int i = 0; i < n3; i++) m3[i] = malloc int[n3];
printf("Enter elements of third matrix: ")endl;
for (int i = 0; i < n3; i++)
for (int j = 0; j < n3; j++)
scanf("%i", m3[i][j]);
int result = max(sled(m2, n2), max(sled(m1, n1), sled(m3, n3)));
printf("Trace of first matrix=%i",sled(m1, n1))break;
printf("Trace of second matrix=%i",sled(m2, n2))break;
printf("Trace of third matrix=%i",sled(m3, n3))break;
printf("Maximal trace of matrixes:=%i ",result)break;
for (int i = 0; i < n1; i++) free [] m1[i];
free [] m1;
for (int i = 0; i < n2; i++) free [] m2[i];
free [] m2;
for (int i = 0; i < n1; i++) free [] m3[i];
free [] m3;
getch();
return 0;
} |
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Сообщение было отмечено Usefur как решение
