Отделить кириллицу от латиницы и несколько своих условий

words_a_z = [x for x in words if re.search('[a-z]', x) if
             x.startswith('var') != True and x.endswith('vz') != True and x[3].isnumeric() != True and x[
                 3].isnumeric() != True and x[9] + x[10].isnumeric() != True and x[15] + x[16] + x[
                 17].isnumeric() != True]

words_a_z = [x for x in words if re.search('[a-z]', x) if x.startswith('var') != True and x.endswith('vz') != True and x[3] != [1, 2, 3, 4, 5, 6] and x[4:8] != 'vartz' and x[9:10].isnumeric() != True and x[11:14] != 'tzvz' and x[15:17].isnumeric() != True]

>>> bool(re.match(r'^var[1-6]vartz\d{2}tzvz\d{3}vz', 'var1vartz02tzvz000vz'))
True

r'^var[1-6]vartz\d{2}tzvz\d{3}vz$'

words_a_z = [x for x in words if re.search('[a-z]', x) if(re.match(r'^var[1-6]vartz\d{2}tzvz\d{3}vz', x)) == True]

import re
 
re_exclude = re.compile(r'var\dvartz\d\dtzvz\d\d\dvz')
words = '''var1vartz02tzvz000vz
var1vartz04tzvz004vz
var1vartz04tzvz008vz
var1vartz04tzvz010vz
var1vartz04tzvz012vz
var1vartz04tzvz016vz
var1vartz04tzvz020vz
somethingdifferent'''.split()
print([word for word in words if not re_exclude.match(word)])

['somethingdifferent']

words_a_z = [x for x in words if re.search('[a-z]', x) if
             x.startswith('var') != True and x.endswith('vz') != True and x[3].isnumeric() != True and x[
                 3].isnumeric() != True and x[9] + x[10].isnumeric() != True and x[15] + x[16] + x[
                 17].isnumeric() != True]

words_a_z = [x for x in words if re.search('[a-z]', x) if x.startswith('var') != True and x.endswith('vz') != True and x[3] != [1, 2, 3, 4, 5, 6] and x[4:8] != 'vartz' and x[9:10].isnumeric() != True and x[11:14] != 'tzvz' and x[15:17].isnumeric() != True]

words_a_z = [x for x in words if re.search('[a-z]', x) if(re.match(r'^var[1-6]vartz\d{2}tzvz\d{3}vz', x)) == True]

def myfilter(line: str) -> bool:
    if len(line) != 20:
        return True
    if line[:3] != 'var':
        return True
    if line[4] not in '123456':
        return True
    #…
    return False
 
print(myfilter('var1vartz04tzvz008vz'))
#ords_a_z = [x for x in words if myfilter(x)]

без_var = [x for x in text_split[1:] if x != 'edmn' if
                                         x != chr(10) if (re.match(r'^var[1-6]vartz\d{2}tzvz\d{3}vz$', x)) != True]

>>> bool(re.match(r'^var[1-6]vartz\d{2}tzvz\d{3}vz$', 'var1vartz07tzvz050vz'))
True

>>> bool(re.match(r'^var[1-6]vartz\d{2}tzvz\d{3}vz$', 'var1vartz07tzvz050vz '))
False